There are N children standing in a line. Each child is assigned a rating value.
You are giving candies to these children subjected to the following requirements:
- Each child must have at least one candy.
- Children with a higher rating get more candies than their neighbors.
What is the minimum candies you must give?
Solution:
Draw a rating value curve, say a[i], it has following case:
1. a[i-1] < a[i] <= a[i+1] --> assign a[i] one more candy than a[i-1]
2. a[i-1] >= a[i] > a[i+1] --> assign a[i] one more candy than a[i+1]
3. a[i] > a[i-1] and a[i] > a[i+1]. --> assign a[i] max(a[i-1],a[i+1]) to meet the second requirement.
4. a[i-1]==a[i]==a[i+1], keep same.
Solution:
Draw a rating value curve, say a[i], it has following case:
1. a[i-1] < a[i] <= a[i+1] --> assign a[i] one more candy than a[i-1]
2. a[i-1] >= a[i] > a[i+1] --> assign a[i] one more candy than a[i+1]
3. a[i] > a[i-1] and a[i] > a[i+1]. --> assign a[i] max(a[i-1],a[i+1]) to meet the second requirement.
4. a[i-1]==a[i]==a[i+1], keep same.
public class Solution {
public int candy(int[] ratings) {
// corner case
int n = ratings.length;
if(n == 0)
return 0;
// initialization
int[] num = new int[n];
Arrays.fill(num,1);
// for increasing ratings
for(int i = 1; i < n; i++){
if(ratings[i] > ratings[i - 1]){
num[i] = num[i-1]+1;
}
}
// for decreasing ratings
for(int i = n-2; i >= 0; i--){
if(ratings[i] > ratings[i + 1] && num[i] <= num[i+1]){
num[i] = num[i+1]+1;
}
}
// count all
int sum = 0;
for(int i : num)
sum += i;
return sum;
}
}

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