Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
Solution:
1. use hash map: O(N) time and O(N) space.(code blow)
2. use slow-fast approach. slow = slow.next while fast = fast.next.next. If there is a cycle, slow and fast would meet.
Can you solve it without using extra space?
Solution:
1. use hash map: O(N) time and O(N) space.(code blow)
2. use slow-fast approach. slow = slow.next while fast = fast.next.next. If there is a cycle, slow and fast would meet.
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
HashMap hash = new HashMap();
while(head != null){
if(!hash.containsKey(head)){
hash.put(head, true);
}
else if(hash.get(head)){
return true;
}
head = head.next;
}
return false;
}
}

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